First, let's expand the expression (2x-1)(2x+1):
(2x-1)(2x+1) = 2x 2x + 2x 1 - 1 2x - 1 = 4x^2 + 2x - 2x - = 4x^2 - 1
Now, let's expand (2x-1)^2:
(2x-1)^2 = (2x-1)(2x-1= 2x 2x + 2x (-1) - 1 2x - 1 (-1= 4x^2 - 2x - 2x + = 4x^2 - 4x + 1
Now, let's add the two expressions together:
(2x-1)(2x+1) + (2x-1)^2 = (4x^2 - 1) + (4x^2 - 4x + 1= 4x^2 - 1 + 4x^2 - 4x + = 8x^2 - 4x
Therefore, (2x-1)(2x+1) + (2x-1)^2 = 8x^2 - 4x.
First, let's expand the expression (2x-1)(2x+1):
(2x-1)(2x+1) = 2x 2x + 2x 1 - 1 2x - 1
= 4x^2 + 2x - 2x -
= 4x^2 - 1
Now, let's expand (2x-1)^2:
(2x-1)^2 = (2x-1)(2x-1
= 2x 2x + 2x (-1) - 1 2x - 1 (-1
= 4x^2 - 2x - 2x +
= 4x^2 - 4x + 1
Now, let's add the two expressions together:
(2x-1)(2x+1) + (2x-1)^2 = (4x^2 - 1) + (4x^2 - 4x + 1
= 4x^2 - 1 + 4x^2 - 4x +
= 8x^2 - 4x
Therefore, (2x-1)(2x+1) + (2x-1)^2 = 8x^2 - 4x.