4(x-3+y)= 4x − 12 + 4y = 4x − 12 + 4y
(а+4)*b+3(b+a)= ab + 4b + 3(b + a) = ab + 4b + 3b + 3a = ab + 7b + 3a
7а+(а+4)*3= 7a + (3a + 12) = 7a + 3a + 12 = 10a + 12
4(x-3+y)= 4x − 12 + 4y = 4x − 12 + 4y
(а+4)*b+3(b+a)= ab + 4b + 3(b + a) = ab + 4b + 3b + 3a = ab + 7b + 3a
7а+(а+4)*3= 7a + (3a + 12) = 7a + 3a + 12 = 10a + 12