To solve this equation, we'll start by squaring both sides to remove the square root:
(x^2 - 2x - 4) = (2x^2 - 6x - 1)
Next, we'll combine like terms and move everything to one side of the equation:
0 = 2x^2 - x + 3
Now, let's factor the quadratic equation:
0 = (2x - 3)(x - 1)
Setting each factor to zero, we get two possible solutions:
2x - 3 = 0x = 3/2
x - 1 = 0x = 1
Therefore, the solutions to the equation sqrt(x^2-2x-4) = sqrt(2x^2-6x-1) are x = 3/2 and x = 1.
To solve this equation, we'll start by squaring both sides to remove the square root:
(x^2 - 2x - 4) = (2x^2 - 6x - 1)
Next, we'll combine like terms and move everything to one side of the equation:
0 = 2x^2 - x + 3
Now, let's factor the quadratic equation:
0 = (2x - 3)(x - 1)
Setting each factor to zero, we get two possible solutions:
2x - 3 = 0
x = 3/2
x - 1 = 0
x = 1
Therefore, the solutions to the equation sqrt(x^2-2x-4) = sqrt(2x^2-6x-1) are x = 3/2 and x = 1.