Дано: (9^(1/3) + a)(3^(1/3) + a)^2 / (a^3 - 3)
(9^(1/3) + a) = ∛9 + a = 2 + a
(3^(1/3) + a) = ∛3 + a
(2 + a)(∛3 + a)^2 / (a^3 - 3)
(2 + a)(3^(2/3) + 2∛3a + a^2) / (a^3 - 3)
(2 + a)(3^(2/3) + 2√3a + a^2) / (a^3 - 3)
(2 + a)(√3+a)(2 + a) / (a-3)
(2 + a)(√3+a)
Ответ: (2 + a)(√3+a)
Дано: (9^(1/3) + a)(3^(1/3) + a)^2 / (a^3 - 3)
(9^(1/3) + a) = ∛9 + a = 2 + a
(3^(1/3) + a) = ∛3 + a
(2 + a)(∛3 + a)^2 / (a^3 - 3)
(2 + a)(3^(2/3) + 2∛3a + a^2) / (a^3 - 3)
(2 + a)(3^(2/3) + 2∛3a + a^2) / (a^3 - 3)
(2 + a)(3^(2/3) + 2√3a + a^2) / (a^3 - 3)
(2 + a)(√3+a)(2 + a) / (a-3)
(2 + a)(√3+a)
Ответ: (2 + a)(√3+a)