To simplify the expression sin(3a+2b)-sin(3a-2b)/cos(3a+2b)+cos(3a-2b), we can use the formula for the difference of sine or cosine:

sin(x) - sin(y) = 2cos((x+y)/2)sin((x-y)/2)
cos(x) + cos(y) = 2cos((x+y)/2)cos((x-y)/2)

Plugging in our values, we get:

(2cos((3a+2b+3a-2b)/2)sin((3a+2b-3a+2b)/2))/(2cos((3a+2b+3a-2b)/2)cos((3a+2b-3a+2b)/2))

Simplifying further, we get:

(2cos(3a)sin(2b))/(2cos(2b)cos(3a))

The 2's cancel out and we are left with:

(cos(3a)sin(2b))/(sin(2b)cos(3a))

sin(2b)/sin(2b) cancels out, leaving us with the final simplification of:

cos(3a)/cos(3a) = 1

Therefore, the simplified expression is 1.