Sin63cos27+cos63sin27

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вопрос

First, we can use the trigonometric identity for the sum of angles for sine and cosine:

sin(A + B) = sinAcosB + cosAsinB

Applying this identity to our expression, we get:

sin(63+27) = sin63cos27 + cos63sin27

Simplifying the expression, we get:

sin(90) = sin63cos27 + cos63sin27

Since sin(90) = 1, we have:

1 = sin63cos27 + cos63sin27

Therefore, the value of the expression sin63cos27 + cos63sin27 is equal to 1.