To solve the system of equations, we can use the substitution method.
First, let's solve the quadratic equation X^2 - 5x + 3 = 0 by factoring or using the quadratic formula.
(X-3)(X-1) = 0X = 3 or X = 1
Now, substitute X=3 and X=1 into the first equation of the system:3 + y = 7y = 4
1 + y = 7y = 6
So the two solutions to the system are:X = 3, y = 4X = 1, y = 6
To solve the system of equations, we can use the substitution method.
First, let's solve the quadratic equation X^2 - 5x + 3 = 0 by factoring or using the quadratic formula.
(X-3)(X-1) = 0
X = 3 or X = 1
Now, substitute X=3 and X=1 into the first equation of the system:
3 + y = 7
y = 4
1 + y = 7
y = 6
So the two solutions to the system are:
X = 3, y = 4
X = 1, y = 6