2х+3(х+y)=11 7(х+3y)-4y=-23 решения сестемы уравнения

Предыдущий
вопрос Следующий
вопрос

1) 2x + 3(x + y) = 11
Simplify the equation:
2x + 3x + 3y = 11
5x + 3y = 11
Rearrange the equation to isolate x:
5x = 11 - 3y
x = (11 - 3y) / 5

2) 7(x + 3y) - 4y = -23
Simplify the equation:
7x + 21y - 4y = -23
7x + 17y = -23
Rearrange the equation to isolate x:
7x = -23 - 17y
x = (-23 - 17y) / 7

Now that we have both x in terms of y, we can set them equal to each other to find a solution:
(11 - 3y) / 5 = (-23 - 17y) / 7
Cross multiply to solve for y:
7(11 - 3y) = 5(-23 - 17y)
77 - 21y = -115 - 85y
Combine like terms:
64 = 64y
y = 1

Now that we have found the value of y, we can substitute it back into one of the original equations to solve for x:
5x = 11 - 3(1)
5x = 8
x = 8/5

Therefore, the solution to the system of equations is x = 8/5, y = 1.