2(y-5)+7=1
2y – 10 + 7 = 1
2y = 1 – 7 + 10
2y = 4
y = 2
2(y-5)+7=1 2y – 10 + 7 = 1 2y = 1 – 7 + 10 2y = 4 y = 2
2(y-5)+7=1
2y – 10 + 7 = 1
2y = 1 – 7 + 10
2y = 4
y = 2
2(y-5)+7=1 2y – 10 + 7 = 1 2y = 1 – 7 + 10 2y = 4 y = 2