2x*x*(x+3)=x*x*(x+6)+64

Предыдущий
вопрос Следующий
вопрос

Expanding both sides of the equation, we get:

2xx(x+3) = 2x^2 * (x+3) = 2x^3 + 6x^2

xx(x+6) + 64 = x^2 * (x+6) + 64 = x^3 + 6x^2 + 64

Setting the two sides equal to each other:

2x^3 + 6x^2 = x^3 + 6x^2 + 64

Rearranging terms:

2x^3 + 6x^2 = x^3 + 6x^2 + 64
2x^3 + 6x^2 = x^3 + 6x^2 + 64
x^3 = 64

Therefore, the solution to the equation is x = 4.