2log5(x)-log2(x)=log2(0,8)

Предыдущий
вопрос Следующий
вопрос

To solve this equation, we can combine the logarithms on the left side of the equation using the properties of logarithms.

First, recall the following properties of logarithms:

Using these properties, we can rewrite the given equation as:

log5(x)^2 - log2(x) = log2(0.8)

Now, we can combine the logarithms on the left side using the first property:

log5(x)^2 / log2(x) = log2(0.8)

Next, we can rewrite log5(x)^2 and log2(x) in terms of a common base, say 10:

(log(x) / log(5))^2 - (log(x) / log(2)) = log2(0.8)

Now, we can simplify the equation further:

(log(x))^2 / (2*log(5)) - log(x) / log(2) = log2(0.8)

Now, we can substitute log2(0.8) = log(0.8) / log(2) = -0.3219 into the equation:

(log(x))^2 / (2*log(5)) - log(x) / log(2) = -0.3219

At this point, we can solve for x, either by substituting log5 and log2 with their respective values and solving numerically or by using a calculator to find the value of x.