log0.25 9 = log(9^(-0.25))9^-0.25 = 1/(9^0.25) = 1/3So, log0.25 9 = log(1/3) = -log(3)
Now, log9 4 = log4/log9 = log2/log3Using the change of base formula,log2/log3 = log2/log9 / log3/log9 = log_9(3)/log_9(9) = 1/2
Therefore, -log(3) 1/2 = -1/2log(3) = -1/2 * log(3) or approximately equal to -0.823.
log0.25 9 = log(9^(-0.25))
9^-0.25 = 1/(9^0.25) = 1/3
So, log0.25 9 = log(1/3) = -log(3)
Now, log9 4 = log4/log9 = log2/log3
Using the change of base formula,
log2/log3 = log2/log9 / log3/log9 = log_9(3)/log_9(9) = 1/2
Therefore, -log(3) 1/2 = -1/2log(3) = -1/2 * log(3) or approximately equal to -0.823.