Expanding both sides, we get:
(x-3)² ≥ x(x-5) + 6
(x-3)(x-3) ≥ x(x-5) + 6x² - 6x + 9 ≥ x² - 5x + 6-6x + 9 ≥ -5x + 6x ≥ 3
Therefore, the solution to the inequality is x ≥ 3.
Expanding both sides, we get:
(x-3)² ≥ x(x-5) + 6
(x-3)(x-3) ≥ x(x-5) + 6
x² - 6x + 9 ≥ x² - 5x + 6
-6x + 9 ≥ -5x + 6
x ≥ 3
Therefore, the solution to the inequality is x ≥ 3.