(Х2+х-5)×(х2+х+1) =-9 ?

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To solve this equation, we need to first expand the expression on the left side using the distributive property:

(х^2 + х - 5) (х^2 + х + 1)
= х^2 х^2 + х^2 х + х^2 1 + х х^2 + х х + х 1 - 5 х^2 - 5 * х - 5

Simplifying this further:

= х^4 + х^3 + х^2 + х^3 + х^2 + х + х - 5х^2 - 5х - 5
= х^4 + 2х^3 + 2х^2 - 4х - 5

Now we can set this expression equal to -9 and solve for x:

х^4 + 2х^3 + 2х^2 - 4х - 5 = -9
х^4 + 2х^3 + 2х^2 - 4х + 5 = 0

This is a quartic equation, which may have multiple solutions. To solve it, we can either use numerical methods or factorization techniques.