To solve this system of equations, we can use the method of substitution or elimination.
Let's use the substitution method.
From the first equation:х + 5у = 27=> х = 27 - 5у
Substitute this value of х into the second equation:2(27 - 5у) - у = -154 - 10у - у = -154 - 11у = -1-11у = -55у = 5
Now substitute the value of у back into one of the original equations to solve for х:х + 5(5) = 27х + 25 = 27х = 2
Therefore, the solution to the system of equations is х = 2 and у = 5.
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the substitution method.
From the first equation:
х + 5у = 27
=> х = 27 - 5у
Substitute this value of х into the second equation:
2(27 - 5у) - у = -1
54 - 10у - у = -1
54 - 11у = -1
-11у = -55
у = 5
Now substitute the value of у back into one of the original equations to solve for х:
х + 5(5) = 27
х + 25 = 27
х = 2
Therefore, the solution to the system of equations is х = 2 and у = 5.