{х+5у=27 2х-у=-1 ришить системой

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To solve this system of equations, we can use the method of substitution or elimination.

Let's use the substitution method.

From the first equation
х + 5у = 2
=> х = 27 - 5у

Substitute this value of х into the second equation
2(27 - 5у) - у = -
54 - 10у - у = -
54 - 11у = -
-11у = -5
у = 5

Now substitute the value of у back into one of the original equations to solve for х
х + 5(5) = 2
х + 25 = 2
х = 2

Therefore, the solution to the system of equations is х = 2 and у = 5.