Задача по SAT. Математическая часть. h = − 4.9t^2 + 25
The equation above expresses the approximat
height h, in meters, of a ball t seconds after it i
launched vertically upward from the ground with a
initial velocity of 25 meters per second. Afte
approximately how many seconds will the ball hit th
ground
A) 3.
B) 4.
C) 4.
D) 5.0
Задача по SAT. Математическая часть. h = − 4.9t^2 + 25
The equation above expresses the approximat
height h, in meters, of a ball t seconds after it i
launched vertically upward from the ground with a
initial velocity of 25 meters per second. Afte
approximately how many seconds will the ball hit th
ground
A) 3.
B) 4.
C) 4.
D) 5.0
The equation above expresses the approximat
height h, in meters, of a ball t seconds after it i
launched vertically upward from the ground with a
initial velocity of 25 meters per second. Afte
approximately how many seconds will the ball hit th
ground
A) 3.
B) 4.
C) 4.
D) 5.0
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To find out when the ball hits the ground, we need to find when the height h is equal to 0.
So, we set the equation h = 0 and solve for t:
0 = -4.9t^2 + 25t
4.9t^2 - 25t =
t(4.9t - 25) = 0
This equation is true when either t = 0 or 4.9t - 25 = 0.
Solving for t in the second part
4.9t - 25 =
4.9t = 2
t = 25 / 4.
t ≈ 5.1
Therefore, the ball will hit the ground after approximately 5 seconds.
The answer is D) 5.0.