Mr(H2O2) = 2*Ar(H)+2*Ar(O) = 2*1+2*16 = 34
ω(H) = (2*Ar(H)/Mr(H2O2))*100% = (2*1/34)*100% ≈ 5,88%
ω(O) = 100%-ω(H) = 100%-5,88% = 94,12%
Ответ: ω(H) =5,88%, ω(O) = 94,12%
Mr(H2O2) = 2*Ar(H)+2*Ar(O) = 2*1+2*16 = 34
ω(H) = (2*Ar(H)/Mr(H2O2))*100% = (2*1/34)*100% ≈ 5,88%
ω(O) = 100%-ω(H) = 100%-5,88% = 94,12%
Ответ: ω(H) =5,88%, ω(O) = 94,12%