X=4-3t x0 , v, s за 2с?

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Given that X = 4 - 3t, let's find the position (x0), velocity (v), and displacement (s) at t = 2s.

Position (x0) at t = 2s:
x0 = 4 - 3(2)
x0 = 4 - 6
x0 = -2

Therefore, the position at t = 2s is x0 = -2.

Velocity (v) at t = 2s:
The velocity can be found by taking the derivative of X with respect to t:
v = dX/dt = d(4 - 3t)/dt = -3

Therefore, the velocity at t = 2s is v = -3.

Displacement (s) at t = 2s:
The displacement can be found by plugging t = 2s into the position equation:
s = 4 - 3(2) - (-2)
s = 4 - 6 + 2
s = 0

Therefore, the displacement at t = 2s is s = 0.