To find the velocity, we need to differentiate the position equation with respect to time.
Given: x = -50 + 5t
When t = 0,x = -50 + 5(0) = -50
When t = 5 minutes (or 5/60 = 1/12 hours),x = -50 + 5(1/12) = -50 + 5/12 = -50 + 0.4167 = -49.5833
Now, to find the velocity (v), we differentiate the position equation with respect to time:
dx/dt = d/dt (-50 + 5t)dx/dt = 5
Therefore, the velocity at x = 80m is 5 m/s.
To find the velocity, we need to differentiate the position equation with respect to time.
Given: x = -50 + 5t
When t = 0,
x = -50 + 5(0) = -50
When t = 5 minutes (or 5/60 = 1/12 hours),
x = -50 + 5(1/12) = -50 + 5/12 = -50 + 0.4167 = -49.5833
Now, to find the velocity (v), we differentiate the position equation with respect to time:
dx/dt = d/dt (-50 + 5t)
dx/dt = 5
Therefore, the velocity at x = 80m is 5 m/s.