4(Х-5)+3(2Х+3)=2(3-3Х)+5(4Х+1)

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вопрос

4(X-5) + 3(2X+3) = 2(3-3X) + 5(4X + 1)

Expanding both sides:

4X - 20 + 6X + 9 = 6 - 6X + 20X + 5

Combine like terms:

10X - 11 = 26X + 11

Move variables to one side and constants to the other side:

10X - 26X = 11 + 11

-16X = 22

Divide by -16 to solve for X:

X = -22/16

Simplified:

X = -11/8