To solve this expression, we need to evaluate each individual trigonometric function at the given angle.
Tg^2(pi/6) = tan(pi/6tan(pi/6) = 1/√Therefore, tan(pi/6)^2 = (1/√3)^2 = 1/3
cos(-pi/3) = cos(pi/3cos(pi/3) = 1/2
sin(-pi/2) = sin(-90 degreessin(-pi/2) = -1
Now we can substitute these values back into the expression.
1/3 - 1/2 - 1 = -2/3 - 1 = -5/3
Therefore, Tg^2(pi/6) - cos(-pi/3) + sin(-pi/2) = -5/3
To solve this expression, we need to evaluate each individual trigonometric function at the given angle.
Tg^2(pi/6) = tan(pi/6
tan(pi/6) = 1/√
Therefore, tan(pi/6)^2 = (1/√3)^2 = 1/3
cos(-pi/3) = cos(pi/3
cos(pi/3) = 1/2
sin(-pi/2) = sin(-90 degrees
sin(-pi/2) = -1
Now we can substitute these values back into the expression.
1/3 - 1/2 - 1 = -2/3 - 1 = -5/3
Therefore, Tg^2(pi/6) - cos(-pi/3) + sin(-pi/2) = -5/3