To find tg α (tangent of α), we use the formula:
tg α = sin α / cos α
Given that cos α = 8/17, we first need to find sin α before we can find tg α.
Since sin^2 α + cos^2 α = 1, we can find sin α:
sin^2 α + (8/17)^2 = 1sin^2 α + 64/289 = 1sin^2 α = 1 - 64/289sin^2 α = 225/289sin α = √(225/289)sin α = 15/17
Now that we have sin α, we can find tg α:
tg α = sin α / cos αtg α = (15/17) / (8/17)tg α = 15/8
Therefore, tg α = 15/8.
To find tg α (tangent of α), we use the formula:
tg α = sin α / cos α
Given that cos α = 8/17, we first need to find sin α before we can find tg α.
Since sin^2 α + cos^2 α = 1, we can find sin α:
sin^2 α + (8/17)^2 = 1
sin^2 α + 64/289 = 1
sin^2 α = 1 - 64/289
sin^2 α = 225/289
sin α = √(225/289)
sin α = 15/17
Now that we have sin α, we can find tg α:
tg α = sin α / cos α
tg α = (15/17) / (8/17)
tg α = 15/8
Therefore, tg α = 15/8.