V(C02)= 67.2 Л _____________ m( C6Н12О6 ) -?

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To calculate the molar mass of C6H12O6 (glucose), we need to add up the atomic masses of all the elements in its chemical formula.

C: 6 atoms x atomic mass of C = 6 x 12.01 = 72.06 g/mol
H: 12 atoms x atomic mass of H = 12 x 1.008 = 12.096 g/mol
O: 6 atoms x atomic mass of O = 6 x 16.00 = 96.00 g/mol

Adding these up:
Molar mass of C6H12O6 = 72.06 + 12.096 + 96.00 = 180.16 g/mol

Now, you can use this molar mass to find the mass of 67.2 L of CO2 in grams and then convert it to moles using the molar mass of C6H12O6.