If 2.8 g of CO and 02 are mixed and reacted to give CO2. How many grams of CO2 can be produced?

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First, we need to determine the limiting reactant in this reaction.

The balanced chemical equation for the reaction is:

2 CO + O2 -> 2 CO2

From the equation, we can see that 2 moles of CO react with 1 mole of O2 to produce 2 moles of CO2.

To find out which reactant is the limiting reactant, we need to calculate the number of moles of each reactant:

Moles of CO = 2.8 g / 28.01 g/mol = 0.1 mo
Moles of O2 = 2.8 g / 32.00 g/mol = 0.0875 mol

Since the stoichiometric ratio of CO to O2 is 2:1, we can see that O2 is the limiting reactant because there is less of it compared to CO.

Now that we know that O2 is the limiting reactant, we can calculate the mass of CO2 that can be produced:

From the balanced equation, we know that 1 mol of O2 produces 2 moles of CO2.

Moles of CO2 = moles of O2 x (2 moles CO2 / 1 mole O2
= 0.0875 mol x 2 = 0.175 mol

Now, we can calculate the mass of CO2 produced:

Mass of CO2 = moles of CO2 x molar mass of CO
= 0.175 mol x 44.01 g/mol = 7.70 g

Therefore, 7.70 grams of CO2 can be produced using the given reactants.