Mr(HCOOH) = 2*Ar(H) + Ar(C) + 2*Ar(O) = 2*1 + 12 + 2*16 = 46
ω(C) = (Ar(C)/Mr(HCOOH))*100% = (12/46)*100% ≈ 26,09%
Ответ: ω(C) = 26,09%
Mr(HCOOH) = 2*Ar(H) + Ar(C) + 2*Ar(O) = 2*1 + 12 + 2*16 = 46
ω(C) = (Ar(C)/Mr(HCOOH))*100% = (12/46)*100% ≈ 26,09%
Ответ: ω(C) = 26,09%