CH4 - CH3CL - C2H6-C2H5Br-C4H10

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вопрос

The given compound is a series of hydrocarbons, each containing varying numbers of carbon and hydrogen atoms with different functional groups attached.

CH4 is methane, the simplest alkane with one carbon atom and four hydrogen atoms.
CH3Cl is chloromethane, an alkyl halide with one carbon atom, three hydrogen atoms, and one chlorine atom.
C2H6 is ethane, an alkane with two carbon atoms and six hydrogen atoms.
C2H5Br is ethyl bromide, an alkyl halide with two carbon atoms, five hydrogen atoms, and one bromine atom.
C4H10 is butane, an alkane with four carbon atoms and ten hydrogen atoms.

Therefore, the given compounds are methane, chloromethane, ethane, ethyl bromide, and butane.