The balanced chemical equation for the reaction between aluminum (Al) and nitric acid (HNO3) forming aluminum nitrate ((Al(NO3)3) with the evolution of nitrogen gas (N2) and water (H2O) is:
2Al + 6HNO3 → 2Al(NO3)3 + 3N2 + 3H2O
This equation shows that 2 moles of aluminum react with 6 moles of nitric acid to produce 2 moles of aluminum nitrate, 3 moles of nitrogen gas, and 3 moles of water.
The balanced chemical equation for the reaction between aluminum (Al) and nitric acid (HNO3) forming aluminum nitrate ((Al(NO3)3) with the evolution of nitrogen gas (N2) and water (H2O) is:
2Al + 6HNO3 → 2Al(NO3)3 + 3N2 + 3H2O
This equation shows that 2 moles of aluminum react with 6 moles of nitric acid to produce 2 moles of aluminum nitrate, 3 moles of nitrogen gas, and 3 moles of water.