CH3COONa --> CH4 --> CH4Br --> C2H6 --> C2H5Cl --> C4H10 --> C4H8 --> C4H10

Предыдущий
вопрос Следующий
вопрос

The reactions are as follows:

CH3COONa (sodium acetate) is subjected to a decarboxylation reaction to yield CH4 (methane).CH4 (methane) undergoes bromination to form CH4Br (methyl bromide).CH4Br (methyl bromide) is then treated with a Grignard reagent to produce C2H6 (ethane).C2H6 (ethane) reacts with HCl to yield C2H5Cl (ethyl chloride).C2H5Cl (ethyl chloride) undergoes a substitution reaction to give C4H10 (butane).C4H10 (butane) can undergo dehydration to form C4H8 (butene).Finally, C4H8 (butene) can be hydrogenated to yield C4H10 (butane) again.