1)С6H14--(t, Pt, -4H4)-->X1--(C2H5Cl, AlCl3)-->X2--(Cl2, hv)--> X3--(KOH спирт)-->X4--(KMnO4)-->X5 2) C--> CaC2-->X1-->C6H6--> X2--> C6H5COOH

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вопрос

1) C6H14 undergoes a dehydration reaction in the presence of heat and platinum catalyst, losing 4 molecules of hydrogen to form X1. X1 then undergoes a Friedel-Crafts alkylation reaction with C2H5Cl and AlCl3 to form X2. X2 is then chlorinated with Cl2 under light to form X3. X3 is then subjected to a reaction with KOH and alcohol to form X4, which is then oxidized with KMnO4 to form the final product X5.

2) Carbon reacts with calcium carbide (CaC2) to form X1. X1 then undergoes a conversion reaction to form benzene (C6H6) as X2. Finally, X2 is further oxidized to form benzoic acid (C6H5COOH).