Ch3CONH2 + NaOH/H2O = CH3COONa + NH3
The reaction between acetamide (CH3CONH2) and sodium hydroxide (NaOH) in water results in the formation of sodium acetate (CH3COONa) and ammonia (NH3).
Ch3CONH2 + NaOH/H2O = CH3COONa + NH3
The reaction between acetamide (CH3CONH2) and sodium hydroxide (NaOH) in water results in the formation of sodium acetate (CH3COONa) and ammonia (NH3).