This is a chemical equation representing a reaction between 2 moles of Boron (B) and 1 mole of Sulfur (S) resulting in the formation of Boron sulfide (B2S3).
2B + S = B2S3
This reaction shows the combination of Boron and Sulfur atoms to form Boron sulfide in a 2:1 ratio.
This is a chemical equation representing a reaction between 2 moles of Boron (B) and 1 mole of Sulfur (S) resulting in the formation of Boron sulfide (B2S3).
2B + S = B2S3
This reaction shows the combination of Boron and Sulfur atoms to form Boron sulfide in a 2:1 ratio.