The given reaction is the conversion of ethyl bromide (C2H5Br) to butane (C4H10) through a substitution reaction.
C2H5Br -> C4H10
This reaction can occur through a series of steps, where the ethyl bromide undergoes nucleophilic substitution to form butane.
C2H5Br + NaOH -> C2H5OH + NaBr (Elimination reaction to form ethanol)C2H5OH -> C4H10 + CH3OOH (Dehydration reaction to form butane and acetic acid)
Therefore, the final products of the reaction of ethyl bromide with NaOH followed by dehydration are butane (C4H10) and acetic acid (CH3OOH).
The given reaction is the conversion of ethyl bromide (C2H5Br) to butane (C4H10) through a substitution reaction.
C2H5Br -> C4H10
This reaction can occur through a series of steps, where the ethyl bromide undergoes nucleophilic substitution to form butane.
C2H5Br + NaOH -> C2H5OH + NaBr (Elimination reaction to form ethanol)
C2H5OH -> C4H10 + CH3OOH (Dehydration reaction to form butane and acetic acid)
Therefore, the final products of the reaction of ethyl bromide with NaOH followed by dehydration are butane (C4H10) and acetic acid (CH3OOH).