To solve this system of equations, we can use the method of substitution.
First, let's solve the first equation for x:
0.5x + 3y = 1.50.5x = 1.5 - 3yx = 3 - 6y
Now, substitute this expression for x into the second equation:
0.5(3 - 6y) - 2y = 41.5 - 3y - 2y = 41.5 - 5y = 4-5y = 2.5y = -0.5
Now that we have found the value of y, we can substitute it back into the first equation to find x:
0.5x + 3(-0.5) = 1.50.5x - 1.5 = 1.50.5x = 3x = 6
Therefore, the solution to the system of equations is x = 6 and y = -0.5.
To solve this system of equations, we can use the method of substitution.
First, let's solve the first equation for x:
0.5x + 3y = 1.5
0.5x = 1.5 - 3y
x = 3 - 6y
Now, substitute this expression for x into the second equation:
0.5(3 - 6y) - 2y = 4
1.5 - 3y - 2y = 4
1.5 - 5y = 4
-5y = 2.5
y = -0.5
Now that we have found the value of y, we can substitute it back into the first equation to find x:
0.5x + 3(-0.5) = 1.5
0.5x - 1.5 = 1.5
0.5x = 3
x = 6
Therefore, the solution to the system of equations is x = 6 and y = -0.5.