{2x + 3 (x + y) - 11 = 0 7 (x + 3y) - 6x + 59 = 0

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вопрос

To solve these equations simultaneously, we can use the method of substitution or elimination. Let's use the substitution method.

Given equations:
1) 2x + 3(x + y) - 11 = 0
2) 7(x + 3y) - 6x + 59 = 0

From equation 1:
2x + 3x + 3y - 11 = 0
5x + 3y - 11 = 0
5x + 3y = 11
=> x = (11 - 3y)/5

Substitute x in equation 2:
7((11 - 3y)/5 + 3y) - 6((11 - 3y)/5) + 59 = 0
7(11 - 3y + 15y)/5 - 6(11 - 3y)/5 + 59 = 0
11(7 - 18y)/5 - 6(11 - 3y)/5 + 59 = 0
(77 - 198y)/5 - (66 - 18y)/5 + 59 = 0
(77 - 198y - 66 + 18y)/5 + 59 = 0
(11 - 180y)/5 + 59 = 0
11 - 180y + 295 = 0
11 - 180y + 295 = 0
284 - 180y = 0
180y = 284
y = 284/180
y = 71/45

Now, substitute the value of y back into the equation for x:
x = (11 - 3(71/45))/5
x = (11 - 213/45)/5
x = (495 - 213)/225
x = 282/225
x = 94/75

So, the solution for the given simultaneous equations is x = 94/75 and y = 71/45.