27^x = 81(3^3)^x = 3^43^(3x) = 3^43x = 4x = 4/3
25^x - 35^x = 10(5^2)^x - 35^x = 105^(2x) - 35^x = 10(5^x)^2 - 35^x - 10 = 0Let y = 5^x, then y^2 - 3y - 10 = 0(y - 5)(y + 2) = 0y = 5 or y = -2
If y = 5:5^x = 5x = 1
If y = -2:5^x = -2 (no real solution)
Therefore, the solution is x = 1.
27^x = 81
(3^3)^x = 3^4
3^(3x) = 3^4
3x = 4
x = 4/3
25^x - 35^x = 10
(5^2)^x - 35^x = 10
5^(2x) - 35^x = 10
(5^x)^2 - 35^x - 10 = 0
Let y = 5^x, then y^2 - 3y - 10 = 0
(y - 5)(y + 2) = 0
y = 5 or y = -2
If y = 5:
5^x = 5
x = 1
If y = -2:
5^x = -2 (no real solution)
Therefore, the solution is x = 1.