1) (\frac{5^7}{5^8} = 5^{7-8} = 5^{-1} = \frac{1}{5})
2) (\frac{16^7}{2^{29}} = 16^7 \cdot 2^{-29} = 2^{28} = 268435456)
1) (\frac{5^7}{5^8} = 5^{7-8} = 5^{-1} = \frac{1}{5})
2) (\frac{16^7}{2^{29}} = 16^7 \cdot 2^{-29} = 2^{28} = 268435456)