To find the solutions for this equation, we can set each factor equal to zero:
2cosx + 1 = cosx = -1/x = 2π/3, 4π/3
√(sinx-1) = √(sinx) = sinx = x = π/2
Therefore, the solutions to the equation are x = π/2, 2π/3, 4π/3.
To find the solutions for this equation, we can set each factor equal to zero:
2cosx + 1 =
cosx = -1/
x = 2π/3, 4π/3
√(sinx-1) =
√(sinx) =
sinx =
x = π/2
Therefore, the solutions to the equation are x = π/2, 2π/3, 4π/3.