To solve this system of equations, we can use the method of substitution or elimination.
Let's start by solving the first equation for one variable.
5x + 3y = 113y = -5x + 11y = (-5/3)x + 11/3
Now, we can substitute this expression for y into the second equation:
8x + 5((-5/3)x + 11/3) = 158x - (25/3)x + (55/3) = 15(24/3)x - (25/3)x = -40/3(-1/3)x = -40/3x = (-40/3) / (-1/3)x = (40/3) * (3/1)x = 40
Now that we have found the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation:
5(40) + 3y = 11200 + 3y = 113y = 11 - 2003y = -189y = -189 / 3y = -63
Therefore, the solution to the system of equations is x = 40 and y = -63.
To solve this system of equations, we can use the method of substitution or elimination.
Let's start by solving the first equation for one variable.
5x + 3y = 11
3y = -5x + 11
y = (-5/3)x + 11/3
Now, we can substitute this expression for y into the second equation:
8x + 5((-5/3)x + 11/3) = 15
8x - (25/3)x + (55/3) = 15
(24/3)x - (25/3)x = -40/3
(-1/3)x = -40/3
x = (-40/3) / (-1/3)
x = (40/3) * (3/1)
x = 40
Now that we have found the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation:
5(40) + 3y = 11
200 + 3y = 11
3y = 11 - 200
3y = -189
y = -189 / 3
y = -63
Therefore, the solution to the system of equations is x = 40 and y = -63.