To solve this equation, we will first expand both sides of the equation:
Left side: (5x+1)(2x-3= 5x(2x) + 5x(-3) + 1(2x) + 1(-3= 10x^2 - 15x + 2x - = 10x^2 - 13x - 3
Right side: (10x-3)(x+1= 10x(x) + 10x(1) - 3(x) - 3(1= 10x^2 + 10x - 3x - = 10x^2 + 7x - 3
Therefore, the equation becomes10x^2 - 13x - 3 = 10x^2 + 7x - 3
Simplify by canceling out the common terms-13x = 7x
Add 13x to both sides-13x + 13x = 7x + 130 = 20x
Rearrangingx = 0
Therefore, the solution to the equation (5x+1)(2x-3) = (10x-3)(x+1) is x = 0.
To solve this equation, we will first expand both sides of the equation:
Left side: (5x+1)(2x-3
= 5x(2x) + 5x(-3) + 1(2x) + 1(-3
= 10x^2 - 15x + 2x -
= 10x^2 - 13x - 3
Right side: (10x-3)(x+1
= 10x(x) + 10x(1) - 3(x) - 3(1
= 10x^2 + 10x - 3x -
= 10x^2 + 7x - 3
Therefore, the equation becomes
10x^2 - 13x - 3 = 10x^2 + 7x - 3
Simplify by canceling out the common terms
-13x = 7x
Add 13x to both sides
-13x + 13x = 7x + 13
0 = 20x
Rearranging
x = 0
Therefore, the solution to the equation (5x+1)(2x-3) = (10x-3)(x+1) is x = 0.