(2x-3)(2x+3)-x^2=12x-69+3x^2

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вопрос

Expanding the left side of the equation:

(2x-3)(2x+3) = 4x^2 + 6x - 6x - 9 = 4x^2 - 9

Substitute this back into the equation:

4x^2 - 9 - x^2 = 12x - 69 + 3x^2

Combine like terms on the right side:

3x^2 - 9 = 15x - 69

Rearrange the equation to set it to zero:

3x^2 - 15x + 60 = 0

Divide by 3:

x^2 - 5x + 20 = 0

This quadratic equation does not have real solutions as the discriminant is negative.