(9*x)/(x+2)+8/(x+2)-x = 0

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To solve this equation, we will first combine the fractions on the left side by finding a common denominator.

(9*x)/(x+2) + 8/(x+2) - x = 0

Combine the fractions:

(9x + 8)/(x+2) - x = 0

Now, find a common denominator for the fractions on the left side (x+2):

(9x + 8 - x(x+2))/(x+2) = 0

Expand the numerator:

(9x + 8 - x^2 - 2x)/(x+2) = 0

Combine like terms:

(7x + 8 - x^2)/(x+2) = 0

Now, set the numerator equal to 0:

7x + 8 - x^2 = 0

Rearrange the terms:

-x^2 + 7x + 8 = 0

Now, solve for x by factoring or using the quadratic formula:

x^2 - 7x - 8 = 0
(x-8)(x+1) = 0

Therefore, x = 8 or x = -1.

So the solutions to the equation are x = 8 and x = -1.