Решите -(7-x)+(3x-14)= -(x+4)-(2x-8)= (21-a)-(20-2a)= -(13+b)+(-b-13)= 2*(3-x)-(8+x)= -4(y+5)+(12-y)=-(7-x)+4(x-5)= -9(y-4)-(12+y)=

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вопрос

1) -(7-x) + (3x-14) = -(x+4) - (2x-8)
-7 + x + 3x - 14 = -x - 4 - 2x + 8
4x - 21 = -3x + 4
4x + 3x = 21 + 4
7x = 25
x = 25/7

2) (21-a) - (20-2a) = 0
21 - a - 20 + 2a = 0
a + 2a = 21 - 20
3a = 1
a = 1/3

3) -(13+b) + (-b-13) = 0
-13 - b - b - 13 = 0
-2b - 26 = 0
-2b = 26
b = -13

4) 2(3-x) - (8+x) = 0
6 - 2x - 8 - x = 0
-3x - 2 = 0
-3x = 2
x = -2/3

5) -4(y+5) + (12-y) = 0
-4y - 20 + 12 - y = 0
-5y - 8 = 0
-5y = 8
y = -8/5

6) -(7-x) + 4(x-5) = 0
-7 + x + 4x - 20 = 0
5x - 27 = 0
5x = 27
x = 27/5

7) -9(y-4) - (12+y) = 0
-9y + 36 - 12 - y = 0
-10y + 24 = 0
-10y = -24
y = 24/10
y = 12/5