To solve the equation Cos(3x-π/6) = Cos(x+π/4), we can use the trigonometric identity Cos(a) = Cos(b) if and only if a = b + 2πn or a = -b + 2πn, where n is an integer.
So, we need to set up two equations:
3x - π/6 = x + π/43x - π/6 = -(x + π/4)
For equation 1 3x - x = π/4 + π/ 2x = 5π/1 x = 5π/24
For equation 2 3x + x = -π/4 + π/ 4x = -π/1 x = -π/48
Therefore, the solutions to the equation Cos(3x-π/6) = Cos(x+π/4) are x = 5π/24 and x = -π/48.
To solve the equation Cos(3x-π/6) = Cos(x+π/4), we can use the trigonometric identity
Cos(a) = Cos(b) if and only if a = b + 2πn or a = -b + 2πn, where n is an integer.
So, we need to set up two equations:
3x - π/6 = x + π/43x - π/6 = -(x + π/4)For equation 1
3x - x = π/4 + π/
2x = 5π/1
x = 5π/24
For equation 2
3x + x = -π/4 + π/
4x = -π/1
x = -π/48
Therefore, the solutions to the equation Cos(3x-π/6) = Cos(x+π/4) are x = 5π/24 and x = -π/48.