Log2(3x+1)log3 x=2 log2(3x+1)

Предыдущий
вопрос Следующий
вопрос

To solve this equation, we can use the properties of logarithms. First, we can combine the logarithms on the left side of the equation using the product rule of logarithms:

log2(3x+1) * log3 x = 2 log2(3x+1)

Next, we can use the power rule of logarithms to rewrite the right side of the equation:

log2(3x+1)^2 = log2((3x+1)^2)

Now, we can set the two expressions equal to each other:

log2(3x+1) * log3 x = log2((3x+1)^2)

Since the bases of the logarithms are the same (both log2), we can drop the logarithms and set the arguments equal to each other:

log3 x = (3x+1)^2

Now, we can exponentiate both sides with base 3 to get rid of the logarithm:

x = 3^((3x+1)^2)

This equation cannot be solved algebraically, but you can approximate the solution using numerical methods or calculators.