1 5/7(d+3)=-2(1-d)

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вопрос

1 5/7(d+3) = -2(1-d)

To solve for d, we first distribute the terms on the left side and the right side of the equation:

1 (d) + 1 (5/7) 3 = -2 1 + 2 * d

d + 15/7 = -2 + 2d

Next, we will isolate d on one side of the equation. Let's first get rid of the fraction:

Multiply through by 7 to get rid of the denominator:

7(d) + 15 = 7(-2) + 7(2d)

7d + 15 = -14 + 14d

Now, let's isolate d by moving all terms with d to one side and the constants to the other side:

-14d - 7d = -14 - 15
-21d = -29

Finally, to solve for d, divide by -21:

d = -29 / -21
d = 29 / 21

Therefore, the solution to the equation is d = 29 / 21.