3/5+x=4/5y-2/7=6/711/25-k=7/25d+2/9=1/9+7/9

Предыдущий
вопрос Следующий
вопрос

To solve each of these equations for the respective variables, we will isolate them one by one.

1) 3/5 + x = 4/5y - 2/7

First, let's isolate x by subtracting 3/5 from both sides
x = 4/5y - 2/7 - 3/
x = 4/5y - 2/7 - 9/3
x = 4/5y - (10/35 + 9/35
x = 4/5y - 19/35

2) 7/25 - k = 7/25d + 2/9

To isolate k, we will subtract 7/25d and 2/9 from both sides
-k = 7/25d + 2/9 - 7/2
-k = 7/25d + 2/9 - 7/2
-k = 7/25d + (2/9 - 7/25
-k = 7/25d + (10/45 - 21/45
-k = 7/25d - 11/4
k = -7/25d + 11/45

3) 1/9 + 7/9 = 3/5d + 2/9

To isolate d, we will first combine the fractions on the left side
8/9 = 3/5d + 2/9

Next, subtract 2/9 from both sides to isolate 3/5d
8/9 - 2/9 = 3/5
6/9 = 3/5
2/3 = 3/5d

Now, divide both sides by 3/5 to solve for d
d = (2/3) / (3/5
d = (2/3) * (5/3
d = 10/9

Therefore, the solutions to the equations are
1) x = 4/5y - 19/3
2) k = -7/25d + 11/4
3) d = 10/9