(6y-1)*(6y+1)-4y(9y+2)=-1

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вопрос

To solve this equation, we will first expand both sides of the equation and then simplify.

Expanding the left side:
(6y-1)(6y+1) = 36y^2 - 6y + 6y - 1 = 36y^2 - 1
-4y(9y+2) = -36y^2 - 8y

Now, substitute these back into the original equation:
36y^2 - 1 - 36y^2 - 8y = -1

Now, simplify the equation:
-1 - 8y = -1
-1 - 8y = -1

Add 1 to both sides:
-8y = 0

Divide by -8:
y = 0

Therefore, the solution to the equation is y = 0.