23 5\34-t=7 9\16+1 7\16

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вопрос

To solve this equation, we need to first subtract the second fraction from both sides of the equation to isolate "t".

23 5/34 - t = 7 9/16 + 1 7/16

23 5/34 - 7 9/16 = 1 7/16 + t

Now we need to convert both mixed numbers to improper fractions:

23 5/34 = (23 34 + 5) / 34 = 797 / 34
7 9/16 = (7 16 + 9) / 16 = 121 / 16
1 7/16 = (1 * 16 + 7) / 16 = 23 / 16

Therefore, the equation becomes:

797/34 - t = 121/16 + 23/16

Now, we can add the fractions on the right side and simplify:

797/34 - t = (121 + 23) / 16
797/34 - t = 144/16
797/34 - t = 9

Now subtract 797/34 from both sides to isolate "t":

-t = 9 - 797/34
-t = 306/34 - 797/34
-t = -491/34

Therefore, the value of "t" is -491/34.