To solve the quadratic equation 4x^2 + 3x - 10 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In this equation, a = 4, b = 3, and c = -10. Substituting these values into the formula, we get:
x = (-3 ± √(3^2 - 44-10)) / 2*x = (-3 ± √(9 + 160)) / x = (-3 ± √169) / x = (-3 ± 13) / 8
Therefore, the solutions to the quadratic equation 4x^2 + 3x - 10 = 0 arex1 = (-3 + 13) / 8 = 10 / 8 = 1.2x2 = (-3 - 13) / 8 = -16 / 8 = -2
So the solutions are x = 1.25 and x = -2.
To solve the quadratic equation 4x^2 + 3x - 10 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In this equation, a = 4, b = 3, and c = -10. Substituting these values into the formula, we get:
x = (-3 ± √(3^2 - 44-10)) / 2*
x = (-3 ± √(9 + 160)) /
x = (-3 ± √169) /
x = (-3 ± 13) / 8
Therefore, the solutions to the quadratic equation 4x^2 + 3x - 10 = 0 are
x1 = (-3 + 13) / 8 = 10 / 8 = 1.2
x2 = (-3 - 13) / 8 = -16 / 8 = -2
So the solutions are x = 1.25 and x = -2.