Для начала найдем значение arccos (3/5):
cos(arccos(3/5)) = 3/5
Теперь найдем sin(2arccos(3/5)):
sin(2arccos(3/5)) = sin(arccos(3/5 + arccos(3/5))= sin(arccos(3/5) + arccos(3/5))= sin(arccos(3/5)) cos(arccos(3/5)) + cos(arccos(3/5)) sin(arccos(3/5))= 3/5 4/5 + 4/5 3/5= 12/25 + 12/25= 24/25
Ответ: 1) 24/25
Для начала найдем значение arccos (3/5):
cos(arccos(3/5)) = 3/5
Теперь найдем sin(2arccos(3/5)):
sin(2arccos(3/5)) = sin(arccos(3/5 + arccos(3/5))
= sin(arccos(3/5) + arccos(3/5))
= sin(arccos(3/5)) cos(arccos(3/5)) + cos(arccos(3/5)) sin(arccos(3/5))
= 3/5 4/5 + 4/5 3/5
= 12/25 + 12/25
= 24/25
Ответ: 1) 24/25